log(1/3)*(2*x + 1) - log(1/3)*(25 + 2*x) > 3 + log(1/3)*(x + 2)
(2*x + 1)*log(1/3) - (2*x + 25)*log(1/3) > (x + 2)*log(1/3) + 3
3 - 26*log(3) (-------------, oo) log(3)
x in Interval.open((3 - 26*log(3))/log(3), oo)
/ 3 - 26*log(3) \ And|x < oo, ------------- < x| \ log(3) /
(x < oo)∧((3 - 26*log(3))/log(3) < x)