log(0.5)*(1 - 3*x) > 2
(1 - 3*x)*log(0.5) > 2
And(1.29513002725931 < x, x < oo)
(1.29513002725931 < x)∧(x < oo)
(1.29513002725931, oo)
x in Interval.open(1.29513002725931, oo)