Tomamos como el límite
$$\lim_{x \to 0^+}\left(\frac{- 3 x^{2} + \left(x^{3} + 2\right)}{- 4 x^{2} + \left(x^{3} + 3\right)}\right)$$
cambiamos
$$\lim_{x \to 0^+}\left(\frac{- 3 x^{2} + \left(x^{3} + 2\right)}{- 4 x^{2} + \left(x^{3} + 3\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\left(x - 1\right) \left(x^{2} - 2 x - 2\right)}{\left(x - 1\right) \left(x^{2} - 3 x - 3\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{- x^{2} + 2 x + 2}{- x^{2} + 3 x + 3}\right) = $$
$$\frac{- 0^{2} + 0 \cdot 2 + 2}{- 0^{2} + 0 \cdot 3 + 3} = $$
= 2/3
Entonces la respuesta definitiva es:
$$\lim_{x \to 0^+}\left(\frac{- 3 x^{2} + \left(x^{3} + 2\right)}{- 4 x^{2} + \left(x^{3} + 3\right)}\right) = \frac{2}{3}$$