Tomamos como el límite
$$\lim_{x \to \frac{2}{3}^+}\left(\frac{5 x + \left(3 x^{2} + 2\right)}{8 x + \left(3 x^{2} + 4\right)}\right)$$
cambiamos
$$\lim_{x \to \frac{2}{3}^+}\left(\frac{5 x + \left(3 x^{2} + 2\right)}{8 x + \left(3 x^{2} + 4\right)}\right)$$
=
$$\lim_{x \to \frac{2}{3}^+}\left(\frac{\left(x + 1\right) \left(3 x + 2\right)}{\left(x + 2\right) \left(3 x + 2\right)}\right)$$
=
$$\lim_{x \to \frac{2}{3}^+}\left(\frac{x + 1}{x + 2}\right) = $$
$$\frac{\frac{2}{3} + 1}{\frac{2}{3} + 2} = $$
= 5/8
Entonces la respuesta definitiva es:
$$\lim_{x \to \frac{2}{3}^+}\left(\frac{5 x + \left(3 x^{2} + 2\right)}{8 x + \left(3 x^{2} + 4\right)}\right) = \frac{5}{8}$$