Tomamos como el límite
$$\lim_{x \to 1^+}\left(\frac{7 x + \left(x^{2} + 10\right)}{9 x + \left(2 x^{2} + 10\right)}\right)$$
cambiamos
$$\lim_{x \to 1^+}\left(\frac{7 x + \left(x^{2} + 10\right)}{9 x + \left(2 x^{2} + 10\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{\left(x + 2\right) \left(x + 5\right)}{\left(x + 2\right) \left(2 x + 5\right)}\right)$$
=
$$\lim_{x \to 1^+}\left(\frac{x + 5}{2 x + 5}\right) = $$
$$\frac{1 + 5}{2 + 5} = $$
= 6/7
Entonces la respuesta definitiva es:
$$\lim_{x \to 1^+}\left(\frac{7 x + \left(x^{2} + 10\right)}{9 x + \left(2 x^{2} + 10\right)}\right) = \frac{6}{7}$$