Sr Examen
Lógica matemática/ notbcorbnotcord

Expresión notbcorbnotcord

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    d∨(b∧(¬c))∨(c∧(¬b))
    $$d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    Simplificación [src]
    $$d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$ 
    d∨(b∧(¬c))∨(c∧(¬b))
    Tabla de verdad 
    +---+---+---+--------+
| b | c | d | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$ 
    d∨(b∧(¬c))∨(c∧(¬b))
    FNDP [src]
    $$d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$ 
    d∨(b∧(¬c))∨(c∧(¬b))
    FNC [src]
    $$\left(b \vee c \vee d\right) \wedge \left(b \vee d \vee \neg b\right) \wedge \left(c \vee d \vee \neg c\right) \wedge \left(d \vee \neg b \vee \neg c\right)$$ 
    (b∨c∨d)∧(b∨d∨(¬b))∧(c∨d∨(¬c))∧(d∨(¬b)∨(¬c))
    FNCD [src]
    $$\left(b \vee c \vee d\right) \wedge \left(d \vee \neg b \vee \neg c\right)$$ 
    (b∨c∨d)∧(d∨(¬b)∨(¬c))
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