Expresión avb&(avc&b)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
b∧(a∨(b∧c))=b∧(a∨c)a∨(b∧(a∨(b∧c)))=a∨(b∧c)
a∨(b∧c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
a∨(b∧c)
Ya está reducido a FND
a∨(b∧c)
(a∨b)∧(a∨c)
(a∨b)∧(a∨c)