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Lógica matemática/ avb》t

Expresión avb》t

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    Solución

    Ha introducido [src] 
    (a∨b)⇒t
    $$\left(a \vee b\right) \Rightarrow t$$
    Solución detallada
    $$\left(a \vee b\right) \Rightarrow t = t \vee \left(\neg a \wedge \neg b\right)$$
    Simplificación [src]
    $$t \vee \left(\neg a \wedge \neg b\right)$$ 
    t∨((¬a)∧(¬b))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | t | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$t \vee \left(\neg a \wedge \neg b\right)$$ 
    t∨((¬a)∧(¬b))
    FNCD [src]
    $$\left(t \vee \neg a\right) \wedge \left(t \vee \neg b\right)$$ 
    (t∨(¬a))∧(t∨(¬b))
    FNC [src]
    $$\left(t \vee \neg a\right) \wedge \left(t \vee \neg b\right)$$ 
    (t∨(¬a))∧(t∨(¬b))
    FNDP [src]
    $$t \vee \left(\neg a \wedge \neg b\right)$$ 
    t∨((¬a)∧(¬b))
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