Expresión (y&xvx¬z)(xv¬y&z(zv¬x&y))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(x∧y)∨(x∧¬z)=x∧(y∨¬z)z∧¬y∧(z∨(y∧¬x))=z∧¬yx∨(z∧¬y∧(z∨(y∧¬x)))=x∨(z∧¬y)(x∨(z∧¬y∧(z∨(y∧¬x))))∧((x∧y)∨(x∧¬z))=x∧(y∨¬z)
x∧(y∨¬z)
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FNC
x∧(y∨¬z)
x∧(y∨¬z)
(x∧y)∨(x∧¬z)
(x∧y)∨(x∧¬z)