Sr Examen

Expresión nota¬b+nota&c

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    Solución

    Ha introducido [src]
    (c∧(¬a))∨((¬a)∧(¬b))
    $$\left(c \wedge \neg a\right) \vee \left(\neg a \wedge \neg b\right)$$
    Solución detallada
    $$\left(c \wedge \neg a\right) \vee \left(\neg a \wedge \neg b\right) = \neg a \wedge \left(c \vee \neg b\right)$$
    Simplificación [src]
    $$\neg a \wedge \left(c \vee \neg b\right)$$
    (¬a)∧(c∨(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$\neg a \wedge \left(c \vee \neg b\right)$$
    (¬a)∧(c∨(¬b))
    FNDP [src]
    $$\left(c \wedge \neg a\right) \vee \left(\neg a \wedge \neg b\right)$$
    (c∧(¬a))∨((¬a)∧(¬b))
    FNCD [src]
    $$\neg a \wedge \left(c \vee \neg b\right)$$
    (¬a)∧(c∨(¬b))
    FND [src]
    $$\left(c \wedge \neg a\right) \vee \left(\neg a \wedge \neg b\right)$$
    (c∧(¬a))∨((¬a)∧(¬b))