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Lógica matemática/ notb*c+b*notc

Expresión notb*c+b*notc

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    Solución

    Ha introducido [src] 
    (b∧(¬c))∨(c∧(¬b))
    $$\left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    Simplificación [src]
    $$\left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$ 
    (b∧(¬c))∨(c∧(¬b))
    Tabla de verdad 
    +---+---+--------+
| b | c | result |
+===+===+========+
| 0 | 0 | 0      |
+---+---+--------+
| 0 | 1 | 1      |
+---+---+--------+
| 1 | 0 | 1      |
+---+---+--------+
| 1 | 1 | 0      |
+---+---+--------+
    FNCD [src]
    $$\left(b \vee c\right) \wedge \left(\neg b \vee \neg c\right)$$ 
    (b∨c)∧((¬b)∨(¬c))
    FNC [src]
    $$\left(b \vee c\right) \wedge \left(b \vee \neg b\right) \wedge \left(c \vee \neg c\right) \wedge \left(\neg b \vee \neg c\right)$$ 
    (b∨c)∧(b∨(¬b))∧(c∨(¬c))∧((¬b)∨(¬c))
    FND [src]
    Ya está reducido a FND
    $$\left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$ 
    (b∧(¬c))∨(c∧(¬b))
    FNDP [src]
    $$\left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$ 
    (b∧(¬c))∨(c∧(¬b))
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