Sr Examen

Expresión Bv(C&!A)v(A&B)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    b∨(a∧b)∨(c∧(¬a))
    $$b \vee \left(a \wedge b\right) \vee \left(c \wedge \neg a\right)$$
    Solución detallada
    $$b \vee \left(a \wedge b\right) \vee \left(c \wedge \neg a\right) = b \vee \left(c \wedge \neg a\right)$$
    Simplificación [src]
    $$b \vee \left(c \wedge \neg a\right)$$
    b∨(c∧(¬a))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$b \vee \left(c \wedge \neg a\right)$$
    b∨(c∧(¬a))
    FNC [src]
    $$\left(b \vee c\right) \wedge \left(b \vee \neg a\right)$$
    (b∨c)∧(b∨(¬a))
    FND [src]
    Ya está reducido a FND
    $$b \vee \left(c \wedge \neg a\right)$$
    b∨(c∧(¬a))
    FNCD [src]
    $$\left(b \vee c\right) \wedge \left(b \vee \neg a\right)$$
    (b∨c)∧(b∨(¬a))