Sr Examen
Lógica matemática/ av(¬a&b&c)

Expresión av(¬a&b&c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    a∨(b∧c∧(¬a))
    a∨(b∧c∧¬a)a \vee \left(b \wedge c \wedge \neg a\right)
    Solución detallada
    a∨(b∧c∧¬a)=a∨(b∧c)a \vee \left(b \wedge c \wedge \neg a\right) = a \vee \left(b \wedge c\right)
    Simplificación [src]
    a∨(b∧c)a \vee \left(b \wedge c\right) 
    a∨(b∧c)
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNCD [src]
    (a∨b)∧(a∨c)\left(a \vee b\right) \wedge \left(a \vee c\right) 
    (a∨b)∧(a∨c)
    FND [src]
    Ya está reducido a FND
    a∨(b∧c)a \vee \left(b \wedge c\right) 
    a∨(b∧c)
    FNC [src]
    (a∨b)∧(a∨c)\left(a \vee b\right) \wedge \left(a \vee c\right) 
    (a∨b)∧(a∨c)
    FNDP [src]
    a∨(b∧c)a \vee \left(b \wedge c\right) 
    a∨(b∧c)
    © Sr Examen – Калькулятор