Expresión xz∨x¬y
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(x∧z)∨(x∧¬y)=x∧(z∨¬y)
x∧(z∨¬y)
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(x∧z)∨(x∧¬y)
Ya está reducido a FNC
x∧(z∨¬y)
x∧(z∨¬y)
(x∧z)∨(x∧¬y)