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Expresión bcdv¬bcdv¬a¬cd

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (b∧c∧d)∨(c∧d∧(¬b))∨(d∧(¬a)∧(¬c))
    (bcd)(cd¬b)(d¬a¬c)\left(b \wedge c \wedge d\right) \vee \left(c \wedge d \wedge \neg b\right) \vee \left(d \wedge \neg a \wedge \neg c\right)
    Solución detallada
    (bcd)(cd¬b)(d¬a¬c)=d(c¬a)\left(b \wedge c \wedge d\right) \vee \left(c \wedge d \wedge \neg b\right) \vee \left(d \wedge \neg a \wedge \neg c\right) = d \wedge \left(c \vee \neg a\right)
    Simplificación [src]
    d(c¬a)d \wedge \left(c \vee \neg a\right)
    d∧(c∨(¬a))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNDP [src]
    (cd)(d¬a)\left(c \wedge d\right) \vee \left(d \wedge \neg a\right)
    (c∧d)∨(d∧(¬a))
    FND [src]
    (cd)(d¬a)\left(c \wedge d\right) \vee \left(d \wedge \neg a\right)
    (c∧d)∨(d∧(¬a))
    FNCD [src]
    d(c¬a)d \wedge \left(c \vee \neg a\right)
    d∧(c∨(¬a))
    FNC [src]
    Ya está reducido a FNC
    d(c¬a)d \wedge \left(c \vee \neg a\right)
    d∧(c∨(¬a))