Sr Examen

Expresión yv!y&!zvx&!zvz

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    y∨z∨(x∧(¬z))∨((¬y)∧(¬z))
    $$y \vee z \vee \left(x \wedge \neg z\right) \vee \left(\neg y \wedge \neg z\right)$$
    Solución detallada
    $$y \vee z \vee \left(x \wedge \neg z\right) \vee \left(\neg y \wedge \neg z\right) = 1$$
    Simplificación [src]
    1
    1
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    1
    1
    FNDP [src]
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1
    FND [src]
    Ya está reducido a FND
    1
    1