Sr Examen
Expresión av¬b&(¬a&¬c)&b
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Solución
Ha introducido
[src]
a∨(b∧(¬a)∧(¬b)∧(¬c))
$$a \vee \left(b \wedge \neg a \wedge \neg b \wedge \neg c\right)$$
Solución detallada
$$b \wedge \neg a \wedge \neg b \wedge \neg c = \text{False}$$
$$a \vee \left(b \wedge \neg a \wedge \neg b \wedge \neg c\right) = a$$
$$a \vee \left(b \wedge \neg a \wedge \neg b \wedge \neg c\right) = a$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+