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Expresión av¬b&(¬a&¬c)&b

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨(b∧(¬a)∧(¬b)∧(¬c))
    $$a \vee \left(b \wedge \neg a \wedge \neg b \wedge \neg c\right)$$
    Solución detallada
    $$b \wedge \neg a \wedge \neg b \wedge \neg c = \text{False}$$
    $$a \vee \left(b \wedge \neg a \wedge \neg b \wedge \neg c\right) = a$$
    Simplificación [src]
    $$a$$
    a
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$a$$
    a
    FNC [src]
    Ya está reducido a FNC
    $$a$$
    a
    FNCD [src]
    $$a$$
    a
    FNDP [src]
    $$a$$
    a