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Lógica matemática/ ¬avc&b&¬c

Expresión ¬avc&b&¬c

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    Solución

    Ha introducido [src] 
    (¬a)∨(b∧c∧(¬c))
    $$\left(b \wedge c \wedge \neg c\right) \vee \neg a$$
    Solución detallada
    $$b \wedge c \wedge \neg c = \text{False}$$
    $$\left(b \wedge c \wedge \neg c\right) \vee \neg a = \neg a$$
    Simplificación [src]
    $$\neg a$$ 
    ¬a
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 0      |
+---+---+---+--------+
    FNCD [src]
    $$\neg a$$ 
    ¬a
    FNDP [src]
    $$\neg a$$ 
    ¬a
    FNC [src]
    Ya está reducido a FNC
    $$\neg a$$ 
    ¬a
    FND [src]
    Ya está reducido a FND
    $$\neg a$$ 
    ¬a
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