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Expresión bc¬dv¬bc¬dv¬a¬dv¬a¬c¬d

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    Solución

    Ha introducido [src]
    ((¬a)∧(¬d))∨(b∧c∧(¬d))∨(c∧(¬b)∧(¬d))∨((¬a)∧(¬c)∧(¬d))
    $$\left(\neg a \wedge \neg d\right) \vee \left(b \wedge c \wedge \neg d\right) \vee \left(c \wedge \neg b \wedge \neg d\right) \vee \left(\neg a \wedge \neg c \wedge \neg d\right)$$
    Solución detallada
    $$\left(\neg a \wedge \neg d\right) \vee \left(b \wedge c \wedge \neg d\right) \vee \left(c \wedge \neg b \wedge \neg d\right) \vee \left(\neg a \wedge \neg c \wedge \neg d\right) = \neg d \wedge \left(c \vee \neg a\right)$$
    Simplificación [src]
    $$\neg d \wedge \left(c \vee \neg a\right)$$
    (¬d)∧(c∨(¬a))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$\neg d \wedge \left(c \vee \neg a\right)$$
    (¬d)∧(c∨(¬a))
    FND [src]
    $$\left(c \wedge \neg d\right) \vee \left(\neg a \wedge \neg d\right)$$
    (c∧(¬d))∨((¬a)∧(¬d))
    FNCD [src]
    $$\neg d \wedge \left(c \vee \neg a\right)$$
    (¬d)∧(c∨(¬a))
    FNDP [src]
    $$\left(c \wedge \neg d\right) \vee \left(\neg a \wedge \neg d\right)$$
    (c∧(¬d))∨((¬a)∧(¬d))