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Lógica matemática/ xyz+!xyz+!z

Expresión xyz+!xyz+!z

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    Solución

    Ha introducido [src] 
    z∨(x∧y∧z)
    $$z \vee \left(x \wedge y \wedge z\right)$$
    Solución detallada
    $$z \vee \left(x \wedge y \wedge z\right) = z$$
    Simplificación [src]
    $$z$$ 
    z
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    $$z$$ 
    z
    FNCD [src]
    $$z$$ 
    z
    FNC [src]
    Ya está reducido a FNC
    $$z$$ 
    z
    FND [src]
    Ya está reducido a FND
    $$z$$ 
    z
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