Expresión (bvcvd)⇒d(avb)va(b⇔d)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
b⇔d=(b∧d)∨(¬b∧¬d)a∧(b⇔d)=a∧(b∨¬d)∧(d∨¬b)(a∧(b⇔d))∨(d∧(a∨b))=(a∧¬b)∨(b∧d)(b∨c∨d)⇒((a∧(b⇔d))∨(d∧(a∨b)))=(a∧¬b)∨(b∧d)∨(¬b∧¬c∧¬d)
(a∧¬b)∨(b∧d)∨(¬b∧¬c∧¬d)
(b∧d)∨(a∧(¬b))∨((¬b)∧(¬c)∧(¬d))
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
(a∧¬b)∨(b∧d)∨(¬b∧¬c∧¬d)
(b∧d)∨(a∧(¬b))∨((¬b)∧(¬c)∧(¬d))
Ya está reducido a FND
(a∧¬b)∨(b∧d)∨(¬b∧¬c∧¬d)
(b∧d)∨(a∧(¬b))∨((¬b)∧(¬c)∧(¬d))
(d∨¬b)∧(a∨b∨¬d)∧(a∨d∨¬c)
(d∨(¬b))∧(a∨b∨(¬d))∧(a∨d∨(¬c))
(b∨¬b)∧(d∨¬b)∧(a∨b∨¬b)∧(a∨b∨¬c)∧(a∨b∨¬d)∧(a∨d∨¬b)∧(a∨d∨¬c)∧(a∨d∨¬d)∧(b∨¬b∨¬c)∧(b∨¬b∨¬d)∧(d∨¬b∨¬c)∧(d∨¬b∨¬d)
(b∨(¬b))∧(d∨(¬b))∧(a∨b∨(¬b))∧(a∨b∨(¬c))∧(a∨b∨(¬d))∧(a∨d∨(¬b))∧(a∨d∨(¬c))∧(a∨d∨(¬d))∧(b∨(¬b)∨(¬c))∧(b∨(¬b)∨(¬d))∧(d∨(¬b)∨(¬c))∧(d∨(¬b)∨(¬d))