Sr Examen

Expresión (bvcvd)⇒d(avb)va(b⇔d)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (b∨c∨d)⇒((a∧(b⇔d))∨(d∧(a∨b)))
    (bcd)((a(bd))(d(ab)))\left(b \vee c \vee d\right) \Rightarrow \left(\left(a \wedge \left(b ⇔ d\right)\right) \vee \left(d \wedge \left(a \vee b\right)\right)\right)
    Solución detallada
    bd=(bd)(¬b¬d)b ⇔ d = \left(b \wedge d\right) \vee \left(\neg b \wedge \neg d\right)
    a(bd)=a(b¬d)(d¬b)a \wedge \left(b ⇔ d\right) = a \wedge \left(b \vee \neg d\right) \wedge \left(d \vee \neg b\right)
    (a(bd))(d(ab))=(a¬b)(bd)\left(a \wedge \left(b ⇔ d\right)\right) \vee \left(d \wedge \left(a \vee b\right)\right) = \left(a \wedge \neg b\right) \vee \left(b \wedge d\right)
    (bcd)((a(bd))(d(ab)))=(a¬b)(bd)(¬b¬c¬d)\left(b \vee c \vee d\right) \Rightarrow \left(\left(a \wedge \left(b ⇔ d\right)\right) \vee \left(d \wedge \left(a \vee b\right)\right)\right) = \left(a \wedge \neg b\right) \vee \left(b \wedge d\right) \vee \left(\neg b \wedge \neg c \wedge \neg d\right)
    Simplificación [src]
    (a¬b)(bd)(¬b¬c¬d)\left(a \wedge \neg b\right) \vee \left(b \wedge d\right) \vee \left(\neg b \wedge \neg c \wedge \neg d\right)
    (b∧d)∨(a∧(¬b))∨((¬b)∧(¬c)∧(¬d))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNDP [src]
    (a¬b)(bd)(¬b¬c¬d)\left(a \wedge \neg b\right) \vee \left(b \wedge d\right) \vee \left(\neg b \wedge \neg c \wedge \neg d\right)
    (b∧d)∨(a∧(¬b))∨((¬b)∧(¬c)∧(¬d))
    FND [src]
    Ya está reducido a FND
    (a¬b)(bd)(¬b¬c¬d)\left(a \wedge \neg b\right) \vee \left(b \wedge d\right) \vee \left(\neg b \wedge \neg c \wedge \neg d\right)
    (b∧d)∨(a∧(¬b))∨((¬b)∧(¬c)∧(¬d))
    FNCD [src]
    (d¬b)(ab¬d)(ad¬c)\left(d \vee \neg b\right) \wedge \left(a \vee b \vee \neg d\right) \wedge \left(a \vee d \vee \neg c\right)
    (d∨(¬b))∧(a∨b∨(¬d))∧(a∨d∨(¬c))
    FNC [src]
    (b¬b)(d¬b)(ab¬b)(ab¬c)(ab¬d)(ad¬b)(ad¬c)(ad¬d)(b¬b¬c)(b¬b¬d)(d¬b¬c)(d¬b¬d)\left(b \vee \neg b\right) \wedge \left(d \vee \neg b\right) \wedge \left(a \vee b \vee \neg b\right) \wedge \left(a \vee b \vee \neg c\right) \wedge \left(a \vee b \vee \neg d\right) \wedge \left(a \vee d \vee \neg b\right) \wedge \left(a \vee d \vee \neg c\right) \wedge \left(a \vee d \vee \neg d\right) \wedge \left(b \vee \neg b \vee \neg c\right) \wedge \left(b \vee \neg b \vee \neg d\right) \wedge \left(d \vee \neg b \vee \neg c\right) \wedge \left(d \vee \neg b \vee \neg d\right)
    (b∨(¬b))∧(d∨(¬b))∧(a∨b∨(¬b))∧(a∨b∨(¬c))∧(a∨b∨(¬d))∧(a∨d∨(¬b))∧(a∨d∨(¬c))∧(a∨d∨(¬d))∧(b∨(¬b)∨(¬c))∧(b∨(¬b)∨(¬d))∧(d∨(¬b)∨(¬c))∧(d∨(¬b)∨(¬d))