Expresión (a*(b*c+a*b))⊕(b*(c⊕b⊕!(a*c)))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧b)∨(b∧c)=b∧(a∨c)a∧((a∧b)∨(b∧c))=a∧b¬(a∧c)=¬a∨¬cb⊕c⊕¬(a∧c)=(a∧¬b)∨(¬b∧¬c)∨(b∧c∧¬a)b∧(b⊕c⊕¬(a∧c))=b∧c∧¬a(a∧((a∧b)∨(b∧c)))⊕(b∧(b⊕c⊕¬(a∧c)))=b∧(a∨c)
b∧(a∨c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∧b)∨(b∧c)
b∧(a∨c)
(a∧b)∨(b∧c)
Ya está reducido a FNC
b∧(a∨c)
