Sr Examen
Expresión ¬((X&(¬y¬z))z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Solución detallada
$$x \wedge z \wedge \neg y \wedge \neg z = \text{False}$$
$$\neg \left(x \wedge z \wedge \neg y \wedge \neg z\right) = 1$$
$$\neg \left(x \wedge z \wedge \neg y \wedge \neg z\right) = 1$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+