Expresión not(a)⇒((b)⇔(c))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$b ⇔ c = \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
$$\neg a \Rightarrow \left(b ⇔ c\right) = a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
$$a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(a \vee b \vee \neg c\right) \wedge \left(a \vee c \vee \neg b\right)$$
$$\left(a \vee b \vee \neg b\right) \wedge \left(a \vee b \vee \neg c\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(a \vee c \vee \neg c\right)$$
(a∨b∨(¬b))∧(a∨b∨(¬c))∧(a∨c∨(¬b))∧(a∨c∨(¬c))
$$a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$
Ya está reducido a FND
$$a \vee \left(b \wedge c\right) \vee \left(\neg b \wedge \neg c\right)$$