Sr Examen
Expresión xyz+x(-z)+(-x)y+(-(x+y+z))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(x∧(¬z))∨(y∧(¬x))∨(x∧y∧z)∨(¬(x∨y∨z))
$$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg x\right) \vee \left(x \wedge y \wedge z\right) \vee \neg \left(x \vee y \vee z\right)$$
Solución detallada
$$\neg \left(x \vee y \vee z\right) = \neg x \wedge \neg y \wedge \neg z$$
$$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg x\right) \vee \left(x \wedge y \wedge z\right) \vee \neg \left(x \vee y \vee z\right) = y \vee \neg z$$
$$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg x\right) \vee \left(x \wedge y \wedge z\right) \vee \neg \left(x \vee y \vee z\right) = y \vee \neg z$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+