Sr Examen

Expresión dbordnotcornotbcornotcb

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (b∧d)∨(b∧(¬c))∨(c∧(¬b))∨(d∧(¬c))
    $$\left(b \wedge d\right) \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right) \vee \left(d \wedge \neg c\right)$$
    Solución detallada
    $$\left(b \wedge d\right) \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right) \vee \left(d \wedge \neg c\right) = d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    Simplificación [src]
    $$d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    d∨(b∧(¬c))∨(c∧(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | b | c | d | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    d∨(b∧(¬c))∨(c∧(¬b))
    FNC [src]
    $$\left(b \vee c \vee d\right) \wedge \left(b \vee d \vee \neg b\right) \wedge \left(c \vee d \vee \neg c\right) \wedge \left(d \vee \neg b \vee \neg c\right)$$
    (b∨c∨d)∧(b∨d∨(¬b))∧(c∨d∨(¬c))∧(d∨(¬b)∨(¬c))
    FNDP [src]
    $$d \vee \left(b \wedge \neg c\right) \vee \left(c \wedge \neg b\right)$$
    d∨(b∧(¬c))∨(c∧(¬b))
    FNCD [src]
    $$\left(b \vee c \vee d\right) \wedge \left(d \vee \neg b \vee \neg c\right)$$
    (b∨c∨d)∧(d∨(¬b)∨(¬c))