Sr Examen
Lógica matemática/ a^(b⇒c)

Expresión a^(b⇒c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    a∧(b⇒c)
    $$a \wedge \left(b \Rightarrow c\right)$$
    Solución detallada
    $$b \Rightarrow c = c \vee \neg b$$
    $$a \wedge \left(b \Rightarrow c\right) = a \wedge \left(c \vee \neg b\right)$$
    Simplificación [src]
    $$a \wedge \left(c \vee \neg b\right)$$ 
    a∧(c∨(¬b))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)$$ 
    (a∧c)∨(a∧(¬b))
    FNCD [src]
    $$a \wedge \left(c \vee \neg b\right)$$ 
    a∧(c∨(¬b))
    FNC [src]
    Ya está reducido a FNC
    $$a \wedge \left(c \vee \neg b\right)$$ 
    a∧(c∨(¬b))
    FND [src]
    $$\left(a \wedge c\right) \vee \left(a \wedge \neg b\right)$$ 
    (a∧c)∨(a∧(¬b))
    © Sr Examen – Калькулятор