Sr Examen
Expresión ¬xy⇒x∨x(y∨z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(y∧(¬x))⇒(x∨(x∧(y∨z)))
$$\left(y \wedge \neg x\right) \Rightarrow \left(x \vee \left(x \wedge \left(y \vee z\right)\right)\right)$$
Solución detallada
$$x \vee \left(x \wedge \left(y \vee z\right)\right) = x$$
$$\left(y \wedge \neg x\right) \Rightarrow \left(x \vee \left(x \wedge \left(y \vee z\right)\right)\right) = x \vee \neg y$$
$$\left(y \wedge \neg x\right) \Rightarrow \left(x \vee \left(x \wedge \left(y \vee z\right)\right)\right) = x \vee \neg y$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+