Sr Examen
Expresión ¬(xy⇒x)∨x(y∨z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
(x∧(y∨z))∨(¬((x∧y)⇒x))
$$\left(x \wedge \left(y \vee z\right)\right) \vee \left(x \wedge y\right) \not\Rightarrow x$$
Solución detallada
$$\left(x \wedge y\right) \Rightarrow x = 1$$
$$\left(x \wedge y\right) \not\Rightarrow x = \text{False}$$
$$\left(x \wedge \left(y \vee z\right)\right) \vee \left(x \wedge y\right) \not\Rightarrow x = x \wedge \left(y \vee z\right)$$
$$\left(x \wedge y\right) \not\Rightarrow x = \text{False}$$
$$\left(x \wedge \left(y \vee z\right)\right) \vee \left(x \wedge y\right) \not\Rightarrow x = x \wedge \left(y \vee z\right)$$
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+