Sr Examen

Expresión notbnotdornotaandnotbc

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ((¬b)∧(¬d))∨(c∧(¬a)∧(¬b))
    $$\left(\neg b \wedge \neg d\right) \vee \left(c \wedge \neg a \wedge \neg b\right)$$
    Solución detallada
    $$\left(\neg b \wedge \neg d\right) \vee \left(c \wedge \neg a \wedge \neg b\right) = \neg b \wedge \left(c \vee \neg d\right) \wedge \left(\neg a \vee \neg d\right)$$
    Simplificación [src]
    $$\neg b \wedge \left(c \vee \neg d\right) \wedge \left(\neg a \vee \neg d\right)$$
    (¬b)∧(c∨(¬d))∧((¬a)∨(¬d))
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    FNCD [src]
    $$\neg b \wedge \left(c \vee \neg d\right) \wedge \left(\neg a \vee \neg d\right)$$
    (¬b)∧(c∨(¬d))∧((¬a)∨(¬d))
    FND [src]
    $$\left(\neg b \wedge \neg d\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(c \wedge \neg b \wedge \neg d\right) \vee \left(\neg a \wedge \neg b \wedge \neg d\right)$$
    ((¬b)∧(¬d))∨(c∧(¬a)∧(¬b))∨(c∧(¬b)∧(¬d))∨((¬a)∧(¬b)∧(¬d))
    FNDP [src]
    $$\left(\neg b \wedge \neg d\right) \vee \left(c \wedge \neg a \wedge \neg b\right)$$
    ((¬b)∧(¬d))∨(c∧(¬a)∧(¬b))
    FNC [src]
    Ya está reducido a FNC
    $$\neg b \wedge \left(c \vee \neg d\right) \wedge \left(\neg a \vee \neg d\right)$$
    (¬b)∧(c∨(¬d))∧((¬a)∨(¬d))