Expresión ((x+!y)*y)+(!x*(y+z))
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Solución
Solución detallada
$$y \wedge \left(x \vee y\right) = y$$
$$\left(y \wedge \left(x \vee y\right)\right) \vee \left(\neg x \wedge \left(y \vee z\right)\right) = y \vee \left(z \wedge \neg x\right)$$
$$y \vee \left(z \wedge \neg x\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$\left(y \vee z\right) \wedge \left(y \vee \neg x\right)$$
Ya está reducido a FND
$$y \vee \left(z \wedge \neg x\right)$$
$$y \vee \left(z \wedge \neg x\right)$$
$$\left(y \vee z\right) \wedge \left(y \vee \neg x\right)$$