Sr Examen
Expresión (¬xy)∨(¬xyz)∨(yzt)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(y∧(¬x))∨(t∧y∧z)∨(y∧z∧(¬x))
$$\left(y \wedge \neg x\right) \vee \left(t \wedge y \wedge z\right) \vee \left(y \wedge z \wedge \neg x\right)$$
Solución detallada
$$\left(y \wedge \neg x\right) \vee \left(t \wedge y \wedge z\right) \vee \left(y \wedge z \wedge \neg x\right) = y \wedge \left(t \vee \neg x\right) \wedge \left(z \vee \neg x\right)$$
Simplificación
[src]
$$y \wedge \left(t \vee \neg x\right) \wedge \left(z \vee \neg x\right)$$
y∧(t∨(¬x))∧(z∨(¬x))
Tabla de verdad
+---+---+---+---+--------+ | t | x | y | z | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 0 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 0 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+
FNCD
[src]
$$y \wedge \left(t \vee \neg x\right) \wedge \left(z \vee \neg x\right)$$
y∧(t∨(¬x))∧(z∨(¬x))
FND
[src]
$$\left(y \wedge \neg x\right) \vee \left(t \wedge y \wedge z\right) \vee \left(t \wedge y \wedge \neg x\right) \vee \left(y \wedge z \wedge \neg x\right)$$
(y∧(¬x))∨(t∧y∧z)∨(t∧y∧(¬x))∨(y∧z∧(¬x))
FNC
[src]
Ya está reducido a FNC
$$y \wedge \left(t \vee \neg x\right) \wedge \left(z \vee \neg x\right)$$
y∧(t∨(¬x))∧(z∨(¬x))