Expresión (¬xy)∨(¬xyz)∨(yzt)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(y∧¬x)∨(t∧y∧z)∨(y∧z∧¬x)=y∧(t∨¬x)∧(z∨¬x)
y∧(t∨¬x)∧(z∨¬x)
Tabla de verdad
+---+---+---+---+--------+
| t | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
y∧(t∨¬x)∧(z∨¬x)
(y∧¬x)∨(t∧y∧z)
(y∧¬x)∨(t∧y∧z)∨(t∧y∧¬x)∨(y∧z∧¬x)
(y∧(¬x))∨(t∧y∧z)∨(t∧y∧(¬x))∨(y∧z∧(¬x))
Ya está reducido a FNC
y∧(t∨¬x)∧(z∨¬x)