Expresión —(x|z)|(y&—z)|—(x|—z)|(y&z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$x | z = \neg x \vee \neg z$$
$$\neg \left(x | z\right) = x \wedge z$$
$$\neg \left(x | z\right) | \left(y \wedge \neg z\right) = 1$$
$$x = \neg x$$
$$\left(x\right) | z = x \vee \neg z$$
$$\left(\left(x\right) | z\right) | \left(y \wedge z\right) = \neg x \vee \neg y \vee \neg z$$
$$\left(\neg \left(x | z\right) | \left(y \wedge \neg z\right)\right) | \left(\left(\left(x\right) | z\right) | \left(y \wedge z\right)\right) = x \wedge y \wedge z$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
$$x \wedge y \wedge z$$
Ya está reducido a FNC
$$x \wedge y \wedge z$$