Sr Examen
Expresión a¬(b)&cv(not(a)vb)&cvc¬(c)
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
(c∧(¬c))∨(a∧c∧(¬b))∨(c∧(b∨(¬a)))
$$\left(c \wedge \neg c\right) \vee \left(c \wedge \left(b \vee \neg a\right)\right) \vee \left(a \wedge c \wedge \neg b\right)$$
Solución detallada
$$c \wedge \neg c = \text{False}$$
$$\left(c \wedge \neg c\right) \vee \left(c \wedge \left(b \vee \neg a\right)\right) \vee \left(a \wedge c \wedge \neg b\right) = c$$
$$\left(c \wedge \neg c\right) \vee \left(c \wedge \left(b \vee \neg a\right)\right) \vee \left(a \wedge c \wedge \neg b\right) = c$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+