Expresión xand(¬yandzandworyand¬w)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(y∧¬w)∨(w∧z∧¬y)=(w∨y)∧(y∨z)∧(¬w∨¬y)x∧((y∧¬w)∨(w∧z∧¬y))=x∧(w∨y)∧(y∨z)∧(¬w∨¬y)
x∧(w∨y)∧(y∨z)∧(¬w∨¬y)
x∧(w∨y)∧(y∨z)∧((¬w)∨(¬y))
Tabla de verdad
+---+---+---+---+--------+
| w | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0 |
+---+---+---+---+--------+
(x∧y∧¬w)∨(x∧y∧¬y)∨(w∧x∧y∧¬w)∨(w∧x∧y∧¬y)∨(w∧x∧z∧¬w)∨(w∧x∧z∧¬y)∨(x∧y∧z∧¬w)∨(x∧y∧z∧¬y)
(x∧y∧(¬w))∨(x∧y∧(¬y))∨(w∧x∧y∧(¬w))∨(w∧x∧y∧(¬y))∨(w∧x∧z∧(¬w))∨(w∧x∧z∧(¬y))∨(x∧y∧z∧(¬w))∨(x∧y∧z∧(¬y))
Ya está reducido a FNC
x∧(w∨y)∧(y∨z)∧(¬w∨¬y)
x∧(w∨y)∧(y∨z)∧((¬w)∨(¬y))
x∧(w∨y)∧(y∨z)∧(¬w∨¬y)
x∧(w∨y)∧(y∨z)∧((¬w)∨(¬y))
(x∧y∧¬w)∨(w∧x∧z∧¬y)