Expresión not(B⊕C)*A
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
b⊕c=(b∧¬c)∨(c∧¬b)¬(b⊕c)=(b∧c)∨(¬b∧¬c)a∧¬(b⊕c)=a∧(b∨¬c)∧(c∨¬b)
a∧(b∨¬c)∧(c∨¬b)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FNC
a∧(b∨¬c)∧(c∨¬b)
(a∧b∧c)∨(a∧b∧¬b)∨(a∧c∧¬c)∨(a∧¬b∧¬c)
(a∧b∧c)∨(a∧b∧(¬b))∨(a∧c∧(¬c))∨(a∧(¬b)∧(¬c))
a∧(b∨¬c)∧(c∨¬b)
(a∧b∧c)∨(a∧¬b∧¬c)