Expresión nota¬b+b&c+nota&c
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Solución
Solución detallada
(b∧c)∨(c∧¬a)∨(¬a∧¬b)=(b∧c)∨(¬a∧¬b)
(b∧c)∨(¬a∧¬b)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(b∧c)∨(¬a∧¬b)
(b∨¬a)∧(b∨¬b)∧(c∨¬a)∧(c∨¬b)
(b∨(¬a))∧(b∨(¬b))∧(c∨(¬a))∧(c∨(¬b))
(b∨¬a)∧(c∨¬b)
Ya está reducido a FND
(b∧c)∨(¬a∧¬b)