Sr Examen
Expresión ¬xy∨x¬y∨¬xyz
El profesor se sorprenderá mucho al ver tu solución correcta😉
⌨
Solución
Ha introducido
[src]
(x∧(¬y))∨(y∧(¬x))∨(y∧z∧(¬x))
$$\left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right) \vee \left(y \wedge z \wedge \neg x\right)$$
Solución detallada
$$\left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right) \vee \left(y \wedge z \wedge \neg x\right) = \left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right)$$
Simplificación
[src]
$$\left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right)$$
(x∧(¬y))∨(y∧(¬x))
Tabla de verdad
+---+---+---+--------+ | x | y | z | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNC
[src]
$$\left(x \vee y\right) \wedge \left(x \vee \neg x\right) \wedge \left(y \vee \neg y\right) \wedge \left(\neg x \vee \neg y\right)$$
(x∨y)∧(x∨(¬x))∧(y∨(¬y))∧((¬x)∨(¬y))
FND
[src]
Ya está reducido a FND
$$\left(x \wedge \neg y\right) \vee \left(y \wedge \neg x\right)$$
(x∧(¬y))∨(y∧(¬x))