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Lógica matemática/ xz(x⇒y)⇒!x+!y+z

Expresión xz(x⇒y)⇒!x+!y+z

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (x∧z∧(x⇒y))⇒(y∨z∨(¬x))
    (x∧z∧(x⇒y))⇒(y∨z∨¬x)\left(x \wedge z \wedge \left(x \Rightarrow y\right)\right) \Rightarrow \left(y \vee z \vee \neg x\right)
    Solución detallada
    x⇒y=y∨¬xx \Rightarrow y = y \vee \neg x
    x∧z∧(x⇒y)=x∧y∧zx \wedge z \wedge \left(x \Rightarrow y\right) = x \wedge y \wedge z
    (x∧z∧(x⇒y))⇒(y∨z∨¬x)=1\left(x \wedge z \wedge \left(x \Rightarrow y\right)\right) \Rightarrow \left(y \vee z \vee \neg x\right) = 1
    Simplificación [src]
    1 
    1
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    1 
    1
    FNC [src]
    Ya está reducido a FNC
    1 
    1
    FNCD [src]
    1 
    1
    FND [src]
    Ya está reducido a FND
    1 
    1
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