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Lógica matemática/ (avb)&cv(a&b&c)&(!cva&b)v(!c&a&bv!a&b&!c)

Expresión (avb)&cv(a&b&c)&(!cva&b)v(!c&a&bv!a&b&!c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    (c∧(a∨b))∨(a∧b∧(¬c))∨(b∧(¬a)∧(¬c))∨(a∧b∧c∧((¬c)∨(a∧b)))
    $$\left(c \wedge \left(a \vee b\right)\right) \vee \left(a \wedge b \wedge \neg c\right) \vee \left(b \wedge \neg a \wedge \neg c\right) \vee \left(a \wedge b \wedge c \wedge \left(\left(a \wedge b\right) \vee \neg c\right)\right)$$
    Solución detallada
    $$a \wedge b \wedge c \wedge \left(\left(a \wedge b\right) \vee \neg c\right) = a \wedge b \wedge c$$
    $$\left(c \wedge \left(a \vee b\right)\right) \vee \left(a \wedge b \wedge \neg c\right) \vee \left(b \wedge \neg a \wedge \neg c\right) \vee \left(a \wedge b \wedge c \wedge \left(\left(a \wedge b\right) \vee \neg c\right)\right) = b \vee \left(a \wedge c\right)$$
    Simplificación [src]
    $$b \vee \left(a \wedge c\right)$$ 
    b∨(a∧c)
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    $$b \vee \left(a \wedge c\right)$$ 
    b∨(a∧c)
    FND [src]
    Ya está reducido a FND
    $$b \vee \left(a \wedge c\right)$$ 
    b∨(a∧c)
    FNCD [src]
    $$\left(a \vee b\right) \wedge \left(b \vee c\right)$$ 
    (a∨b)∧(b∨c)
    FNC [src]
    $$\left(a \vee b\right) \wedge \left(b \vee c\right)$$ 
    (a∨b)∧(b∨c)
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