Expresión yv(x⇔z)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$x ⇔ z = \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right)$$
$$y \vee \left(x ⇔ z\right) = y \vee \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right)$$
$$y \vee \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
$$y \vee \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right)$$
$$\left(x \vee y \vee \neg x\right) \wedge \left(x \vee y \vee \neg z\right) \wedge \left(y \vee z \vee \neg x\right) \wedge \left(y \vee z \vee \neg z\right)$$
(x∨y∨(¬x))∧(x∨y∨(¬z))∧(y∨z∨(¬x))∧(y∨z∨(¬z))
Ya está reducido a FND
$$y \vee \left(x \wedge z\right) \vee \left(\neg x \wedge \neg z\right)$$
$$\left(x \vee y \vee \neg z\right) \wedge \left(y \vee z \vee \neg x\right)$$