Sr Examen

Expresión not(not(a*b+not(a)*c))

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬(¬((a∧b)∨(c∧(¬a))))
    ¬(¬((ab)(c¬a)))\neg \left(\neg \left(\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)\right)\right)
    Solución detallada
    ¬((ab)(c¬a))=(a¬b)(¬a¬c)\neg \left(\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)\right) = \left(a \wedge \neg b\right) \vee \left(\neg a \wedge \neg c\right)
    ¬(¬((ab)(c¬a)))=(ab)(c¬a)\neg \left(\neg \left(\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)\right)\right) = \left(a \wedge b\right) \vee \left(c \wedge \neg a\right)
    Simplificación [src]
    (ab)(c¬a)\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)
    (a∧b)∨(c∧(¬a))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    (ab)(c¬a)\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)
    (a∧b)∨(c∧(¬a))
    FND [src]
    Ya está reducido a FND
    (ab)(c¬a)\left(a \wedge b\right) \vee \left(c \wedge \neg a\right)
    (a∧b)∨(c∧(¬a))
    FNC [src]
    (ac)(a¬a)(bc)(b¬a)\left(a \vee c\right) \wedge \left(a \vee \neg a\right) \wedge \left(b \vee c\right) \wedge \left(b \vee \neg a\right)
    (a∨c)∧(b∨c)∧(a∨(¬a))∧(b∨(¬a))
    FNCD [src]
    (ac)(b¬a)\left(a \vee c\right) \wedge \left(b \vee \neg a\right)
    (a∨c)∧(b∨(¬a))