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Expresión avb&(cv¬avavc)&¬b

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    a∨(b∧(¬b)∧(a∨c∨(¬a)))
    $$a \vee \left(b \wedge \neg b \wedge \left(a \vee c \vee \neg a\right)\right)$$
    Solución detallada
    $$a \vee c \vee \neg a = 1$$
    $$b \wedge \neg b \wedge \left(a \vee c \vee \neg a\right) = \text{False}$$
    $$a \vee \left(b \wedge \neg b \wedge \left(a \vee c \vee \neg a\right)\right) = a$$
    Simplificación [src]
    $$a$$
    a
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$a$$
    a
    FND [src]
    Ya está reducido a FND
    $$a$$
    a
    FNDP [src]
    $$a$$
    a
    FNC [src]
    Ya está reducido a FNC
    $$a$$
    a