Sr Examen
Expresión cv~(a&b)+b~c
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Solución
Ha introducido
[src]
c⇔(b∨c∨(¬(a∧b)))
$$c ⇔ \left(b \vee c \vee \neg \left(a \wedge b\right)\right)$$
Solución detallada
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$b \vee c \vee \neg \left(a \wedge b\right) = 1$$
$$c ⇔ \left(b \vee c \vee \neg \left(a \wedge b\right)\right) = c$$
$$b \vee c \vee \neg \left(a \wedge b\right) = 1$$
$$c ⇔ \left(b \vee c \vee \neg \left(a \wedge b\right)\right) = c$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+