Expresión xy∨xz∨¬x¬yz
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(x∧y)∨(x∧z)∨(z∧¬x∧¬y)=(x∧y)∨(z∧¬y)
(x∧y)∨(z∧¬y)
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(x∧y)∨(z∧¬y)
Ya está reducido a FND
(x∧y)∨(z∧¬y)
(x∨z)∧(x∨¬y)∧(y∨z)∧(y∨¬y)
(x∨z)∧(y∨z)∧(x∨(¬y))∧(y∨(¬y))
(x∨¬y)∧(y∨z)