Expresión (AvB)&(BvC)&(AvC)⇒A&B&C
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∨b)∧(a∨c)∧(b∨c)=(a∧b)∨(a∧c)∨(b∧c)((a∨b)∧(a∨c)∧(b∨c))⇒(a∧b∧c)=(¬a∧¬b)∨(¬a∧¬c)∨(¬b∧¬c)∨(a∧b∧c)
(¬a∧¬b)∨(¬a∧¬c)∨(¬b∧¬c)∨(a∧b∧c)
(a∧b∧c)∨((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬b)∧(¬c))
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∨¬a∨¬b)∧(a∨¬a∨¬c)∧(a∨¬b∨¬c)∧(b∨¬a∨¬b)∧(b∨¬a∨¬c)∧(b∨¬b∨¬c)∧(c∨¬a∨¬b)∧(c∨¬a∨¬c)∧(c∨¬b∨¬c)∧(a∨¬a∨¬b∨¬c)∧(b∨¬a∨¬b∨¬c)∧(c∨¬a∨¬b∨¬c)
(a∨(¬a)∨(¬b))∧(a∨(¬a)∨(¬c))∧(a∨(¬b)∨(¬c))∧(b∨(¬a)∨(¬b))∧(b∨(¬a)∨(¬c))∧(b∨(¬b)∨(¬c))∧(c∨(¬a)∨(¬b))∧(c∨(¬a)∨(¬c))∧(c∨(¬b)∨(¬c))∧(a∨(¬a)∨(¬b)∨(¬c))∧(b∨(¬a)∨(¬b)∨(¬c))∧(c∨(¬a)∨(¬b)∨(¬c))
(¬a∧¬b)∨(¬a∧¬c)∨(¬b∧¬c)∨(a∧b∧c)
(a∧b∧c)∨((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬b)∧(¬c))
Ya está reducido a FND
(¬a∧¬b)∨(¬a∧¬c)∨(¬b∧¬c)∨(a∧b∧c)
(a∧b∧c)∨((¬a)∧(¬b))∨((¬a)∧(¬c))∨((¬b)∧(¬c))
(a∨¬b∨¬c)∧(b∨¬a∨¬c)∧(c∨¬a∨¬b)
(a∨(¬b)∨(¬c))∧(b∨(¬a)∨(¬c))∧(c∨(¬a)∨(¬b))