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Ecuación diferencial lncosydx+xtanydy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
  d                                      
x*--(y(x))*tan(y(x)) + log(cos(y(x))) = 0
  dx                                     
$$x \tan{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} + \log{\left(\cos{\left(y{\left(x \right)} \right)} \right)} = 0$$
x*tan(y)*y' + log(cos(y)) = 0
Respuesta [src]
 y(x)                            
   /                             
  |                              
  |     tan(y)                   
  |  ----------- dy = C1 - log(x)
  |  log(cos(y))                 
  |                              
 /                               
                                 
$$\int\limits^{y{\left(x \right)}} \frac{\tan{\left(y \right)}}{\log{\left(\cos{\left(y \right)} \right)}}\, dy = C_{1} - \log{\left(x \right)}$$
Clasificación
separable
1st exact
almost linear
separable reduced
lie group
separable Integral
1st exact Integral
almost linear Integral
separable reduced Integral