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Ecuación diferencial x^2*y''-x*y'+y=x/log(x)+log(x)/x

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
     2                                            
 2  d            d                   x      log(x)
x *---(y(x)) - x*--(y(x)) + y(x) = ------ + ------
     2           dx                log(x)     x   
   dx                                             
$$x^{2} \frac{d^{2}}{d x^{2}} y{\left(x \right)} - x \frac{d}{d x} y{\left(x \right)} + y{\left(x \right)} = \frac{x}{\log{\left(x \right)}} + \frac{\log{\left(x \right)}}{x}$$
x^2*y'' - x*y' + y = x/log(x) + log(x)/x
Respuesta [src]
        1                      log(x)                                     
y(x) = --- + C1*x - x*log(x) + ------ + C2*x*log(x) + x*log(x)*log(log(x))
       4*x                      4*x                                       
$$y{\left(x \right)} = C_{1} x + C_{2} x \log{\left(x \right)} + x \log{\left(x \right)} \log{\left(\log{\left(x \right)} \right)} - x \log{\left(x \right)} + \frac{\log{\left(x \right)}}{4 x} + \frac{1}{4 x}$$
Clasificación
nth linear euler eq nonhomogeneous variation of parameters
nth linear euler eq nonhomogeneous variation of parameters Integral