Sr Examen

Ecuación diferencial y''-cos(x)y'+sin(x)y=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
                                  2          
              d                  d           
sin(x)*y(x) - --(y(x))*cos(x) + ---(y(x)) = 0
              dx                  2          
                                dx           
$$y{\left(x \right)} \sin{\left(x \right)} - \cos{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 0$$
y*sin(x) - cos(x)*y' + y'' = 0
Respuesta [src]
          /     2           4    2       3                  4    2          \        /                2           2    2       3    3       3              \        
          |    x *sin(x)   x *sin (x)   x *cos(x)*sin(x)   x *cos (x)*sin(x)|        |    x*cos(x)   x *sin(x)   x *cos (x)   x *cos (x)   x *cos(x)*sin(x)|    / 6\
y(x) = C2*|1 - --------- + ---------- - ---------------- - -----------------| + C1*x*|1 + -------- - --------- + ---------- + ---------- - ----------------| + O\x /
          \        2           24              6                   24       /        \       2           6           6            24              12       /        
$$y{\left(x \right)} = C_{2} \left(\frac{x^{4} \sin^{2}{\left(x \right)}}{24} - \frac{x^{4} \sin{\left(x \right)} \cos^{2}{\left(x \right)}}{24} - \frac{x^{3} \sin{\left(x \right)} \cos{\left(x \right)}}{6} - \frac{x^{2} \sin{\left(x \right)}}{2} + 1\right) + C_{1} x \left(- \frac{x^{3} \sin{\left(x \right)} \cos{\left(x \right)}}{12} + \frac{x^{3} \cos^{3}{\left(x \right)}}{24} - \frac{x^{2} \sin{\left(x \right)}}{6} + \frac{x^{2} \cos^{2}{\left(x \right)}}{6} + \frac{x \cos{\left(x \right)}}{2} + 1\right) + O\left(x^{6}\right)$$
Clasificación
2nd power series ordinary