Sr Examen

Ecuación diferencial y''+sin(x)y'+cos(x)y=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
                                  2          
d                                d           
--(y(x))*sin(x) + cos(x)*y(x) + ---(y(x)) = 0
dx                                2          
                                dx           
$$y{\left(x \right)} \cos{\left(x \right)} + \sin{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 0$$
y*cos(x) + sin(x)*y' + y'' = 0
Respuesta [src]
          /     2           4    2       4    2              3              \        /                2           3    3       2    2       3              \        
          |    x *cos(x)   x *cos (x)   x *sin (x)*cos(x)   x *cos(x)*sin(x)|        |    x*sin(x)   x *cos(x)   x *sin (x)   x *sin (x)   x *cos(x)*sin(x)|    / 6\
y(x) = C2*|1 - --------- + ---------- - ----------------- + ----------------| + C1*x*|1 - -------- - --------- - ---------- + ---------- + ----------------| + O\x /
          \        2           24               24                 6        /        \       2           6           24           6               12       /        
$$y{\left(x \right)} = C_{2} \left(- \frac{x^{4} \sin^{2}{\left(x \right)} \cos{\left(x \right)}}{24} + \frac{x^{4} \cos^{2}{\left(x \right)}}{24} + \frac{x^{3} \sin{\left(x \right)} \cos{\left(x \right)}}{6} - \frac{x^{2} \cos{\left(x \right)}}{2} + 1\right) + C_{1} x \left(- \frac{x^{3} \sin^{3}{\left(x \right)}}{24} + \frac{x^{3} \sin{\left(x \right)} \cos{\left(x \right)}}{12} + \frac{x^{2} \sin^{2}{\left(x \right)}}{6} - \frac{x^{2} \cos{\left(x \right)}}{6} - \frac{x \sin{\left(x \right)}}{2} + 1\right) + O\left(x^{6}\right)$$
Clasificación
2nd power series ordinary